(2x-5)(x^2+4x-6)=0

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Solution for (2x-5)(x^2+4x-6)=0 equation:


Simplifying
(2x + -5)(x2 + 4x + -6) = 0

Reorder the terms:
(-5 + 2x)(x2 + 4x + -6) = 0

Reorder the terms:
(-5 + 2x)(-6 + 4x + x2) = 0

Multiply (-5 + 2x) * (-6 + 4x + x2)
(-5(-6 + 4x + x2) + 2x * (-6 + 4x + x2)) = 0
((-6 * -5 + 4x * -5 + x2 * -5) + 2x * (-6 + 4x + x2)) = 0
((30 + -20x + -5x2) + 2x * (-6 + 4x + x2)) = 0
(30 + -20x + -5x2 + (-6 * 2x + 4x * 2x + x2 * 2x)) = 0
(30 + -20x + -5x2 + (-12x + 8x2 + 2x3)) = 0

Reorder the terms:
(30 + -20x + -12x + -5x2 + 8x2 + 2x3) = 0

Combine like terms: -20x + -12x = -32x
(30 + -32x + -5x2 + 8x2 + 2x3) = 0

Combine like terms: -5x2 + 8x2 = 3x2
(30 + -32x + 3x2 + 2x3) = 0

Solving
30 + -32x + 3x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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